Question

Can someone help me with derivatives and chain rule...
Find derivative of
(t^3 + 1 )^(100)
sqrt(1-x^2)

Answer 1

\[(t ^{3} + 1)^{100}\]

Answer 2

\[\sqrt{1-x ^{2}}\]

Answer 3

So you first multiply everything on the inside of the parenthesis by 100 for the top equation and raise it to 100-1...Then you multiply all of that by the derivative of everything inside the parenthesis

Answer 4

so it would be \[100(t ^{2}+1)^{99} x 2t\]

Answer 5

\[100t ^{3} + 100\]

Answer 6

where did you get x2t?

Answer 7

x is multiplying- 2t is the derivative of what is inside the parenthesis

Answer 8

can you explain how you got the derivative of the inside parenthesis adn explain about x

Answer 9

Sorry, there is no x- i just used x to imply multiplication. The derivative of the inside is the derivative of t^2 which is 2t plus the derivative of 1 which is 0

Answer 10

Oh ok so when you multiply through what do you get?

Answer 11

200t(t ^{2}+1)^{99}

Answer 12

\[200t(t ^{2}+1)^{99}\]

Answer 13

I kept getting online \[300t^2(t^3 +1) ^(99)\]

Answer 14

that is raised to 99

Answer 15

Ah crap- i saw t^2 instead of t^3---that would be right then

Answer 16

ok cool... what about the second one

Answer 17

and how again did you get 2t as the inside derivative