Can someone help me with derivatives and chain rule...
Find derivative of
(t^3 + 1 )^(100)
sqrt(1-x^2)

Question

Can someone help me with derivatives and chain rule...
Find derivative of 
(t^3 + 1 )^(100)
sqrt(1-x^2)

anonymous · Answer

$$(t ^{3} + 1)^{100}$$

anonymous · Answer

$$\sqrt{1-x ^{2}}$$

anonymous · Answer

So you first multiply everything on the inside of the parenthesis by 100 for the top equation and raise it to 100-1...Then you multiply all of that by the derivative of everything inside the parenthesis

anonymous · Answer

so it would be $$100(t ^{2}+1)^{99} x 2t$$

anonymous · Answer

$$100t ^{3} + 100$$

anonymous · Answer

where did you get x2t?

anonymous · Answer

x is multiplying- 2t is the derivative of what is inside the parenthesis

anonymous · Answer

can you explain how you got the derivative of the inside parenthesis adn explain about x

anonymous · Answer

Sorry, there is no x- i just used x to imply multiplication.  The derivative of the inside is the derivative of t^2 which is 2t plus the derivative of 1 which is 0

anonymous · Answer

Oh ok so when you multiply through what do you get?

anonymous · Answer

200t(t ^{2}+1)^{99}

anonymous · Answer

$$200t(t ^{2}+1)^{99}$$

anonymous · Answer

I kept getting online $$300t^2(t^3 +1) ^(99)$$

anonymous · Answer

that is raised to 99

anonymous · Answer

Ah crap- i saw t^2 instead of t^3---that would be right then

anonymous · Answer

ok cool... what about the second one

anonymous · Answer

and how again did you get 2t as the inside derivative