If it requires 7.0 J of work to stretch a particular spring by 2.3 cm from its equilibrium length, how much more work will be required to stretch it an additional 3.9 cm?
Recall that work is defined as\[W = \int\limits F dx\]and that the force of a spring is\[F_s = kx\]Substituting \[W = \int\limits kx dx\]Integrating\[W = {1 \over 2} k x^2\] Therefore, with the given data, we can determine the spring constant. Once we know the spring constant, we can determine the additional work required to stretch the spring the additional 3.9 cm. Watch your units. x here should be in meters.
the k is very high
k=26465 your ans is around 40. something
thanks eashmore that helped a lot and yes mythias that is what I got and it turned out to be correct
ok perfect :)
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