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evaluate the double integral: xcos(y)DA, D is bounded by y=0, y=x^2, x=1
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\[\int\limits \int\limits xcos(y)\]
i got to \[\int\limits_{0}^{1}xsin(x^{2})dX\]
then I'm stuck
u-sub\[u=x^2\implies du=2xdx\]
so 1/2(cos x^2) from 0 to 1?
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figured it out! thanks!
-1/2cos, but yeah
So does this just yield \[\frac {1}{2} - \frac {1}{2}\cos(1)\] ?
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