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Mathematics 9 Online
OpenStudy (anonymous):

Please help me...I'm desperate... Attachment...

OpenStudy (anonymous):

OpenStudy (anonymous):

Well let's see... Let's look at angle BAD first. What is the angle of A in that triangle? You know 2 of the angles so you can find the third.

OpenStudy (anonymous):

Then you will need to find the length of the "hose". To do this it is fairly easy. Pythagorean's Theorm states that a^2 + b^2 = c^2. So in this case: a = 24 b = 18 c = *the length we want* So 24^2 + 18^2 = ? (30) The length of the hose is 30.

OpenStudy (mysesshou):

\[24^2+18^2=(BD)^2\] Solve for BD length. Using the 60deg in angle A and the length of BD, you can find the length of AD So, using SOH CAH TOA, choose TOA So, tan(60)=BD/AD AD= BD/tan(60)

OpenStudy (mysesshou):

I guess Krewe is more thorough :)

OpenStudy (anonymous):

I'm still extremly confused... I'm sorry...I just suck so bad with math OTL

OpenStudy (mysesshou):

Did you understand through Krewe's post?

OpenStudy (anonymous):

Now we can find the length of AD. We have the 60degree angle right there in the triangle, so let's use it! The side we want to find in this problem is considered the "adjacent" side. So we will use Tan in this case, since we have its opposite counterpart. This is how we will set it up: \[\tan(60) = \left(\begin{matrix}30 \\ a\end{matrix}\right)\] So now we are going to want "a" by itself so we can find its value. Just multiply a on both sides to get: \[a \tan(60) = 30\] Then just divide tan(60) on both sides to get: \[a = \left(\begin{matrix}30 \\ \tan(60)\end{matrix}\right)\] Solve for a and you have your answer to part 1!

OpenStudy (anonymous):

A little...you see I have dyscalculia so math never something I'll never really get... >.<

OpenStudy (anonymous):

Sorry :\ I'm trying to explain each part as thorough as I can. What are you confused on? Which steps?

OpenStudy (anonymous):

It's okay..I think I'm just gonna talk to my teacher..she'll proably set me up with more tutoring which I don't mind. But I really want to thank you guys. I understand it just a little bit more without getting as confused <3

OpenStudy (anonymous):

It's fine! Go ahead and ask any questions. I can explain it better I am sure ;P

OpenStudy (anonymous):

You should be my teacher xDD

OpenStudy (mysesshou):

Ok, did you get the first part, with the Pythagorean's Theorem?

OpenStudy (anonymous):

Yes! I also realized that I should use it on the rest of my work sheet. I sumbitted the ones I did on my own and got the work sheet completed with a 89 :D I'm homeschooled so my test results come as fast as I sumbit em xD

OpenStudy (anonymous):

Thank you guys again ^^

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