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Mathematics 20 Online
OpenStudy (curry):

cosx/1-tanx + sinx/1-cotx = cosx + sinx

OpenStudy (curry):

prove

OpenStudy (curry):

and rewrite this in terms of only ssinx and cossx

OpenStudy (curry):

co^2(2x-sin2x

OpenStudy (curry):

cos^2(2x)-sin(2x)

Directrix (directrix):

[cosx/(1-tanx)] +[ sinx/(1-cotx)] = cosx + sinx Is this the problem? I wanted to be sure which terms are in a denominator.

OpenStudy (curry):

ye

Directrix (directrix):

Let's try some things. What is [(1-tanx)] *[(1-cotx)] =

OpenStudy (curry):

um 1-tan-cot+1

Directrix (directrix):

So, 2 - tanx - cotx ? Yes?

OpenStudy (curry):

ye

Directrix (directrix):

Some people begin these proofs by changing terms to be all sines and cosines. Others look for a way to get a common denominator and hope terms will add out. Do you have a preference for one way or another?

OpenStudy (curry):

nope

Directrix (directrix):

I'm going to the DRAW and convert to sines and cosines and see what happens. I need you to check as we go along. This approach may work and may not work in terms of producing what we want but that's the way it goes with trig identities. Looking at what we are trying to show: cosx + sinx on the right side makes me think sines and cosines is the way to go.

OpenStudy (curry):

and quick side question how woulod u solve sin(2x)= 0.5 i got to sinxcosx=0.25

Directrix (directrix):

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