for the given polynomial P(x) and the given c, use the remainder theorem to fid P(c).
P(x)=3x^3-7x^2-2x+5 ; c=-3
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OpenStudy (experimentx):
-133
OpenStudy (anonymous):
how did you get that?
OpenStudy (experimentx):
put the value x=-3,
it seems that x+3 is not factor of P(x)
OpenStudy (anonymous):
so for this one
P(x)=4x^4+x^2-2 ; c= -1
if it doesnt equal 0 its not a factor?
OpenStudy (anonymous):
or does it have to equal the the value of c?
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OpenStudy (experimentx):
yup ...
OpenStudy (experimentx):
no ... it must be zero if x+1 is a factor of P(x)
OpenStudy (experimentx):
let me say again ... if x+a is a factor of P(x) then p(-a) must be equal to zero
OpenStudy (anonymous):
ohh ok
when plugging in c to p(x)
it must equal 0 for it to be a factor
OpenStudy (experimentx):
for example we have P(x) = x^2 - 3x + 2
now we have P(-1) = 0, so, x+1 is factor of P(x)
and so is x-2,
but P(5) != 0 therefore x-5 is not factor of P(x)
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OpenStudy (anonymous):
ohh
can you do just this one
P(x)=4x^4+x^2-2 ; c= -1
OpenStudy (experimentx):
P(-1) = 4 + 1 - 2 = 3 != 0 so x+1 is not a factor of P(x)