Question

Easy, try it out guys,

Given 6 different toys of green colour, 5 different toys of blue colour and 4 different toys of red colour, the combination of toys that can be chosen taking atleast one green and one blue toys are ?

Answer 1

@Ishaan94

Answer 2

how many are you choosing each time?

Answer 3

what type of question does this category follow to probability ?

Answer 4

@Callisto: Any combination ;-)

Answer 5

@pokemon23: Combinatorics

Answer 6

Interesting when do you learn combinatorics?

Answer 7

should i list out all possibility ?

Answer 8

Is it (11)9! ? heh :$

Answer 9

i think ' the combination of .... are' is not the same as ' how many combinations ..'? :S

Answer 10

\( (2^6-1)\times (2^5-1)\times 2^4 \)

Answer 11

You can do it in two ways:
1)6C1x5C1(4C0+4C1+4C2+4C3+4C4)+6C2x5C1(4C0+4C1+4C2+4C3+4C4)+6C3x5C1(4C0+4C1+4C2+4C3+4C4)+.......+6C6x5C1(4C0+4C1+4C2+4C3+4C4)..
=5C1(6C0+6C1+6C2+6C3+...6C6)(4C0+4C1+4..

2)The total no of ways of choosing atleast one from 6 green balls is (2^6-1)
The total no of ways of choosing atleast one from 5 blue balls is (2^5-1)
The total no of ways of choosing any from 4 red balls is (2^4)

Both will give the same answer! xD