Question

the product of 2 positive intergers is 90 find the 2 intergers if the larger is 3 more than twice the smaller

Answer 1

x= the smaller
2x+3= the larger
\[x(2x+3)=90\]

Answer 2

\[2x^2+3x-90=0\]

Answer 3

\[(2x+15)(x-6)=0\]

Answer 4

\[2x+15=0\]
\[x-6=0\]

Answer 5

Discard 2x+15=0 because -15/2 is not positive and is not an integer.

Answer 6

\[x=6\]

Answer 7

\[2x+3=15\]

Answer 8

So the integers and 6 and 15

Answer 9

it was cut off the work of the intergers