Question

If h(-2)=3 and h'(-2) =4 find dy/dx(h(x)/x) at x=-2?

Answer 1

d/dx[h(x)/x] = (x*h' - h(x)*1)/x^2

Answer 2

d/dx[h(x)/x] at x=-2 is
((-2)*(4) - (3)*1)/(-2)^2
=(-8 - 3)/4
= -11/4

Answer 3

I just used the quotient rule

Answer 4

can somebody check this?

Answer 5

wait, i think your substitutions are wrong

Answer 6

just kdiding

Answer 7

@jaersyn, where?

Answer 8

:)

Answer 9

Thank you everyone