Question

Could you help me?

Answer 1

check b^2-4ac

Answer 2

How many do you think? Guess. Note that this is a quadratic .

Answer 3

Is it 2?

Answer 4

if it is greater than zero, there are 2 solution. If it is less than 0, there are no solutions, and they are complex conjugates. If it is 0, there is one repeated solution.

Answer 5

Could you put that in english? lol

Answer 6

b^2-4ac.
Greater than zero -> 2
Equal to zero -> 1
Less than zero -> none.

Answer 7

o.
check disctiminant D = b^2-4ac (after comparing with std equation)

if its zero, then on eunique solution. less than zero, no real solution. greater than zero, then 2 real solutions

Answer 8

How do I find the answer?

Answer 9

b^2-4ac. Greater than zero -> 2 Equal to zero -> 1 Less than zero -> none.
In this case, a=-3, b=1, c=-4

Answer 10

So, are there 2 solutions?

Answer 11

There are NONE.

Answer 12

Are you sure your correct? If so, 2 medals

Answer 13

you could also just solve it right?

Answer 14

I'm bad at math. :P

Answer 15

Dude, FIND b^2-4ac, and tell me what you get.

Answer 16

0?

Answer 17

Dude. a=-3, b=1, c=-4
Find b squared minus four a times c.

Answer 18

1^2 - 4(-3)(-4)

Answer 19

thus there are no solutions because the answer is less than 0.

Answer 20

okay 1 medal, because you were being rude. :P

Answer 21

lolol whtv. look up quadratic discriminant if you need more hep.

Answer 22

You could've been a little nicer

Answer 23

I could've been more helpful. I'm not trying to be helpful though. I'm trying to solve as many problems as quickly as I can.

Answer 24

Im learning this stuff. :P

Answer 25

But 0 is correct, right?

Answer 26

Comon' guys.

Answer 27

Yes, dude 0 is the ansewr. I think.

Answer 28

I think? and I GAVE you a medal :(

Answer 29

later people :P