Question

derivative of y= (1/(e^(3x) +x^2))

Answer 1

y=(e^(3x) +x^2)^(-1)
y'=-(e^(3x)+x^2)^(-2)*[3e^(3x)+2x]

Answer 2

could you help with
f(z)=1/(e^z+1)^2

Answer 3

and show steps?

Answer 4

\[f(z)=\frac{1}{(e^z+1)^2}\]?

Answer 5

you need chain rule for this. maybe easiest to rewrite in exponential notation as
\[f(z)=(e^z+1)^{-2}\]

Answer 6

then
\[f'(z)=-2(e^z+1)^{-3}\times e^z\] by the chian rule

Answer 7

clean up as
\[f'(z)=\frac{-2e^z}{(e^z+1)^3}\]

Answer 8

thanks!

Answer 9

could you help me with more of an application type?

Answer 10

http://www.wiley.com/college/sc/hugheshallett/chap3.pdf
Page 131 number 52 and 54