How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl? Show all of the work needed to solve this problem.

Zn (s) + 2 HCl (aq) - ZnCl2 (aq) + H2 (g)

Question

How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl? Show all of the work needed to solve this problem. 

Zn (s) + 2 HCl (aq)  -> ZnCl2 (aq) + H2 (g)

rogue · Answer

mol = molarity x volume
n = MV
5.4 L * 2.8 M HCl = 15.12 mol HCl

According to the balanced reaction, for every 2 moles of HCl, you need 1 mole of Zn to react. So for 15.12 mol HCl, you need 15.12/2 = 7.56 mol Zn. Now the molar mass of 65.4 g/mol. So in 7.56 mol Zn, there are 7.56 mol * 65.4 g/mol = 494. g Zn.

So you need 494 grams of zinc to react completely with 5.4 liters of 2.8 M HCl.

anonymous · Answer

No.. This is not a practice exam. This is a module quiz from FLVS and it's cheating if you use this answer. Plus it has a obvious mistake in it. Mr. Carlyle 
FLVS Chemistry Instructor 

This question is a violation of the OpenStudy Guidelines. The question is from an online school plus a violation by solicitation for members to unknowingly assist them cheating on an exam. 30653065chem30653065

baseballguy101 · Answer

lmao ive seen that same message everywhere. Don't believe the "it has an obvious mistake" its bs