Ask
your own question, for FREE!
Mathematics
21 Online
OpenStudy (anonymous):
The function g(x,y) = x^4+y^3 has a critical point at (0,0). What sort of critical point is it?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
derivative is 0 at that point i think..looking at the graph soo
OpenStudy (anonymous):
There is suppossed to be some kind of method to determine this
OpenStudy (anonymous):
yeah i cheated, i'm not this far into calc yet roflmao
OpenStudy (anonymous):
wait, roflmao don't you just plug in the values? you get 0 + 0
OpenStudy (anonymous):
that's the "0" critical point (no idea what the term is) as opposed to the "does not exist" critical point
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
zarkon can u help me?
OpenStudy (zarkon):
you could try the 2nd derivative test...but it will fail
OpenStudy (zarkon):
looks like a saddle point to me
OpenStudy (anonymous):
well its a saddle point i think
OpenStudy (anonymous):
i dont get it
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (zarkon):
if you fix x at zero and let y range then you get |dw:1332474475405:dw|
if you fix y at zero and let x range then you get |dw:1332474504780:dw|
OpenStudy (anonymous):
ok
OpenStudy (zarkon):
looks like a saddle :)
OpenStudy (anonymous):
thanks
OpenStudy (zarkon):
np
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!