Please help! f(x)= {-7x^2+6x for x less than 0 and 6x^2-2 for x greater than or equal to 0}
Compute the left and right hand limits: x approaches 0

Question

Please help! f(x)= {-7x^2+6x for x less than 0 and 6x^2-2 for x greater than or equal to 0}
Compute the left and right hand limits: x approaches 0

phi · Answer

for x < 0,  you have f(x)=-7x^2+6x
what is f(x) when x is a small negative number approaching 0?

phi · Answer

for x>0,   f(x)= 6x^2-2
when x-->0    do you see that 6x^2 --> 0  and f(x)= 0-2= -2 in the limit?

anonymous · Answer

Yes I see that now

phi · Answer

what do you get for left hand limit ?  (x is the the left of 0  i.e. negative, but approaching 0)

anonymous · Answer

I thought it would be 0 but it is not correct

phi · Answer

-7x^2+6x approaches 0.  Are you sure this is the correct expression?

anonymous · Answer

Yes, maybe the system is glitching? Because I thought it would be 0, -2, and f'(0) DNE