Question

If (sin A)/(sin B) = p and (cos A)/(cos B)=q , find tan A and tan B

Answer 1

tan = sin/cos, so would tan A just be (Sin A/Cos A)?
if so, then the answer would be (pSinB)/(qCosB)....
similarly, tan B should be (sinA/p)/(cosA/q)

Answer 2

sinA/sinB = p ---> sinA = psinB
cosA/cosB = q ---> cosA = qcosB

so,
tanA = sinA/cosA = (psinB)/(qcosB) = p/q*tanB
tanB = [sinA/p]/[cosA/q] = [qsinA]/[pcosA] = q/p*tanA
???