What is the sum of a 30–term arithmetic sequence where the first term is 74 and the last term is –100?
probably you can use the formula sum of terms = (a+l)*n/2 where a = first term l = last term n = number of terms i think you've got all the unknowns what you need to do is to substitute the numbers into the formula and get the answer
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sn = n(a1 + an)/2 a30 = -100 a1 = 74 s30 = 30(74 -100)/2 s30 = 30(26)/2 s30 = 390
I didm't read the question properly, my apologies. \[15 \times (74-100) = ? \]
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