Question

why is this the complete ground state electron configuration of a phosphorous atom?

1s^2 2s^2 2p^3 3s^2 3p^3

I was taught the numbers in the exponents must equal the number of electrons and these numbers do not add up

Answer 1

There's a mistake with the 2p orbitals for the config. you have.
Phosphorus has 15 electrons in the ground state, so its configuration should be\[P: 1s^2 2s^2 2p^6 3s^2 3p^3\]

Answer 2

but the powers add up to 13

Answer 3

shouldnt they add up to 15?

Answer 4

Yes, they should. The one that the textbook/techer gave you is wrong.

Answer 5

thanks for letting me know. can you work with me please? Im preparing for a test. I have some more questions

Answer 6

calculate the frequency of red light at 650nm

Answer 7

the correct answer to this is 4.6 x 10^14 s^-1 but i dont see how. I got different exponents

Answer 8

That's an easy one.\[c = f \lambda\]c is a constant, its the speed of light, which is approx 3 x 10^8 m/s. f is frequency and lambda is wavelength.

Answer 9

c/f right?

Answer 10

but convert nm to m first

Answer 11

\[f = \frac {c}{\lambda}\]And yes, convert to meters first.

Answer 12

3.00 x 10^8/ 6.5 x 10^-7

Answer 13

i just get 4.61

Answer 14

no exp

Answer 15

nvm

Answer 16

actually explain sorry

Answer 17

:P negative exp

Answer 18

huh

Answer 19

I think you entered it in the calculator wrong

Answer 20

yea i figured thanks

Answer 21

Alright, np =)

Answer 22

while we are on frequency...

A photon has a frequency of 6.5 x 10^3 MHz. Convert this frequency into wavelength, in nm

Answer 23

Same equation, convert MHz to Hz; solve for lambda. Hertz is just s^-1 btw.

Answer 24

6500000 Hz

Answer 25

3.00 x 10^8/6500000 = 46.153m

Answer 26

46.153m x 10^9nm= 4.615 x 10^10....the correct exp is suppose to be 7

Answer 27

The freq should be 6.5 x 10^9 Hz

Answer 28

6.5 x 10^3 (1000)?

Answer 29

thats what i entered and it gave me 6500000

Answer 30

6.5 x 10^3 MHz = 6.5 x 10^3 x 10^6 Hz = 6.5 GHz = 6.5 x 10^9 Hz

Answer 31

6500 megahertz to hertz...

Answer 32

ok

Answer 33

i see

Answer 34

whats after that

Answer 35

c/f?

Answer 36

yeah.

Answer 37

3.00 x 10^8/ 6.5 x 10^9

Answer 38

??

Answer 39

thanks

Answer 40

another question

Answer 41

Place the following in order of decreasing radius
Br^(-), Kr, Se^(2-), Sr^(2+), Rb^(+)

Answer 42

Br^- has 35 protons and 36 electrons. Kr has 36 protons and 36 electrons. Rb^+ has 37 protons and 36 electrons. Sr^(2+) has 38 protons and 36 electrons.

Think about the effective nuclear charge. The stronger the pull of the nucleus, the closer in electrons will go. All of the have the same # of electrons, but different # of protons. The one with the highest # of protons has the strongest pull and so the smallest radius. So the order in decreasing radius is
Br^-, Kr, Rb^+, Sr^(2+)

Answer 43

wow thanks for that brilliant explanation

Answer 44

the electron spin quantum number has two possible values +1/2 and -1/2...how do you determine the value

for instance when
n=3
l=0
Ml=0

Ms= +1/2

and when
n=3
l=0
Ml=0

Ms= -1/2