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Mathematics 12 Online
OpenStudy (anonymous):

How can i get the proyection of the intersection of this two surfaces into the plane YZ?

OpenStudy (anonymous):

OpenStudy (anonymous):

The surfaces are: \[y=1-x\] and \[z=1-x^2\]

OpenStudy (anonymous):

any idea myko?

OpenStudy (anonymous):

sec

OpenStudy (anonymous):

the intersection is the set of points (x, 1-y,1-x2) to get a proyection to yz plane, make x=0

OpenStudy (anonymous):

sry, where i wrote 1-y should be 1-x

OpenStudy (anonymous):

Don't worry. So the set of points is (0,1,1)?

OpenStudy (anonymous):

looks like

OpenStudy (anonymous):

y=z

OpenStudy (anonymous):

yeah!

OpenStudy (anonymous):

I got the same.

OpenStudy (anonymous):

gj

OpenStudy (anonymous):

z = 1 - x^2, y = 1-x

OpenStudy (anonymous):

so z = (1-x)(1+x) = y(1+x)

OpenStudy (anonymous):

making x = 0, gives z = y

OpenStudy (anonymous):

ya, thats right

OpenStudy (anonymous):

Thank you myko! =)

OpenStudy (anonymous):

you did it by your self, gj

OpenStudy (anonymous):

what is gj?

OpenStudy (anonymous):

good job

OpenStudy (anonymous):

ahhh thank you =). You gave me the idea.!

OpenStudy (anonymous):

:)

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