Question

log6 (x+4) - log6 (x-2)= log6 (x)

Answer 1

\[\log_{6} (x+4) - \log_{6} (x-2= \log_{6} (x+4)/(x-2) = \log_{6} x\]
then take exponential (base 6 ofcource) bouth sides and solve equation

Answer 2

i dont understand how you get x from that

Answer 3

taking exponential
\[6^{\log 6 (x+4)/(x−2)}= 6^{\log 6 x}\]
(x+4)/(x-2) =x
x+4 = x(x-2)
and solve

Answer 4

you should get x=4 and x=-1

Answer 5

how does x(x-2) equal out to -1?

Answer 6

\[x^{2} -3x -4 =0\]

Answer 7

ohh. alright thanks. i understand now

Answer 8

this is what u get if u pass all terms to one side x+4 = x(x-2)

Answer 9

thank you, can you help me with some other problems on my profile?

Answer 10

log6 (x + 4) - log6(x-2) = log6(x)
log6 [ (x + 4) / (x + 2) ] = log6(x)
[ (x + 4) / (x + 2) ] = x
x^2 - 2x = x + 4
x^2 - 3x - 4 = 0
(x - 4) (x + 1) = 0
x = 4 or x = -1
x = 4 (x = -1 is an extraneous solution)