hello need help,plotting differentiattion graph,but am totally confuse in this case as my cn's are {-2,0)
and my hyper cn's {-3,0).how do i do this in the graph?

Question

hello need help,plotting differentiattion graph,but am totally confuse in this case as my cn's are {-2,0)
and my hyper cn's {-3,0).how do i do this in the graph?

anonymous · Answer

This are my given equation$$f(x)=2(x+1)/x^2 ,     f \prime(x)=-2(x+2)/x^3        and   f \prime \prime(x)=4(x+3)/x^4$$

anonymous · Answer

@dpaInc

anonymous · Answer

i'm confused.  what are you trying to do?

anonymous · Answer

derivatives are correct...

anonymous · Answer

Application of differentiation
Graphing

anonymous · Answer

oh, I see.  graph f using f' and f''.  is that right?

anonymous · Answer

yeah exactly!!!

anonymous · Answer

have taken some steps already,can given u my answers if u like,but cant actually do the graphing cos my asnwers look confusing to me

anonymous · Answer

ok let's start with f first. domain of f is any x except x=0...  you'll have an asymptote there.

anonymous · Answer

are there any zeros of f?

anonymous · Answer

yeah positive in both left and right

anonymous · Answer

my horizontal asympto is 0
y=0

anonymous · Answer

correct for horizontal asymptote.  
but do you have any zero's?  (yes, horizontal asymptotes CAN be crossed)

anonymous · Answer

as in? u mean my intercepts? or my relative(local)extrema?

anonymous · Answer

zeros = x-intercept(s)

anonymous · Answer

(-1,0)

anonymous · Answer

good.  this is what we have so far...
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