Question

totally lost please help, use implicit diffe. to find dy/dx, 2xy+y^2=x+y

Answer 1

y(x)1-2y/2x+2y-1

Answer 2

Totally lost sounds bad. Do you know how to differentiate implicitly?.

Answer 3

Lolz totally

Answer 4

yes thats the answer but again, im lost, @ no data, no sir =(

Answer 5

mon is when my profesor went over this and i was snowed in.

Answer 6

well but maybe you can diferentiante something like this: y = x^2

Answer 7

using dy/dx?

Answer 8

yeah!. and what is the do you get by differentiate y = x^2?

Answer 9

2x/y?

Answer 10

Mmm that was close look: \[\frac{dy}{dx}=2x\]

Answer 11

ok i get that.

Answer 12

It's very important that you know how to get the derivative of explicit functions. By the way, what is the difference between and explict function and an implicit function?

Answer 13

Ok suppose that we have to get the derivative of yx = x^3

Answer 14

You have to use the chain rule. Do you know what rule is that?

Answer 15

yes i do

Answer 16

f'(x)+f(g(x))?

Answer 17

Mmm not exactly.

Answer 18

the chain rule can be written as \[\frac{dy}{dx}=\frac{dy}{du}\frac{du}{dx}\]

Answer 19

Let's apply this chain rule to the equation a wrote before.

Answer 20

\[yx=x^3\]

Answer 21

taking the derivative on both sides of the equation.

Answer 22

\[\frac{d}{dx}(yx)=\frac{d}{dx}(x^3)\]

Answer 23

\[\frac{dy}{dx}\frac{dx}{dx}=3x^2\]

Answer 24

is that the answer?

Answer 25

No, it's an example. You need to apply the same rule to your problem.

Answer 26

no i mean to ur example, is that the answer?

Answer 27

yeah.

Answer 28

kk.ima give a go, thanks for the time, i really do appreciate it

Answer 29

You're welcome!