Question

i have no clue how to solve this

Answer 1

All you do is plug in x = whatever wherever you see an x. So, for f(1) you are doing it for x = 1. So, plug in 1 everywhere you see an x: \[(3(1)^2-4(1)+1)/(3(1)-1)=(3-4+1)/(3-1)=0/2=0\]

Answer 2

You still here?

Answer 3

yeah im still here

Answer 4

That's a pretty impressive question! Here's where we start... Let's see if the top can factor first...

Answer 5

would i start by canceling out the 3 on the top and bottom?

Answer 6

No, you can't cancel them because they are not factors. You want to factor first and then cancel things.

Answer 7

The reason you can't cancel like that is similar to the reason you can't do this: