Question

How many solutions does this system of equations have?

x-4y=13

5x-20y=63

Answer 1

for the 2nd equation, take out 5 as the common factor on the left hand side , and divide both sides by 5, can you show me what would you get?

Answer 2

would it have none?

Answer 3

if you take out the common factor
5x-20y=63
5(x-4y) = 63
then divide both sides by 5
5(x-4y) /5= 63/5
(x-4) = 63/5

Answer 4

so it would be infinite??

Answer 5

it would only have 1.Correct??

Answer 6

after that , rewrite the 2 equations
x-4y=13 => x-4y-13 =0
(x-4y) = 63/5 => x-4y -63/5 =0
So , you can see that they have the same slope, but different y-int
So they are //lines, like this

So how many intercept(s) can you see?

Answer 7

1

Answer 8

where?

Answer 9

What i the answer??

Answer 10

is*

Answer 11

sorry i won't give you the answer directly this time.. you should work it out yourself

Answer 12

have you ever seen 2 parallel lines having intercept(s) ?