Question

In the reaction 2Al + 3 MnO ---> Al2O3 +3Mn
220g Al and 400g of MnO are mixed,
which substance is remained in access after the reaction and by how much \?
Ive got that Al will remain at the en by 4.32g

Answer 1

at the end of the question after 4.32 its Moles not gram
please check my answer

Answer 2

Mn will remain in exces as it is 5.7mol and Al2O3 is 1.90 moles so we can say mn will be in excess by 3.8 ok

Answer 3

but here MnO is the limitng reagent naa
???

Answer 4

ha and they are asking which remain not which get consume :P

Answer 5

how can u say that Al2O3 is 1.9 mole

Answer 6

cal krk :P

Answer 7

arre haan wo to theek hai
3--->1
=> 5.6 ---> 5.6/3
= 1.89

Answer 8

look u find limiting reagent is MNO ok now u see its coefficeint is 3 ant its mole is 5.7 now cal that AL2O3 coefficeint is 1 so its mole is 1.90 now u see for Mn in a same way and u find coeffiecint is same dat is 3 means its mole is 5.7 now u see that no. of mole of Mn is max dan Al2O3

Answer 9

whose mole max means excess amount :) and by how much jusst subtract the value :)

Answer 10

now for 1 Al2O3 -- 2 Al
==> 1.9 Al2O3-- 3.8 Al
now left is 8.14-3.8= 4.32

Answer 11

ye mera DIMAAAG hai

Answer 12

arrey limiting reaent is MnO so y u touch Al

Answer 13

OHHHOOOO
maine question hi galat samajh liya tha
ek baat batao Al kitna use hua
main sirf reactants dekh rha th jabki last me product bhi to hai
hmmmmm....got it

Answer 14

dekho Al k mole 8.4 h and MnO k 5.7 now u see MnO is limiting reagent here means 5.7 mole i used from both of the reactantss ok
u knw VJ sir k chem he is awesome** :)