A certain particle has a lifetime of 1x10^-7s when measured at rest. How far does it go before decaying, its speed is 0.99c when it is created?

Question

anonymous · Answer

this question is on time dialation, please anyone help.

nottim · Answer

Ha. I almost thought we could use d=vt here.

nottim · Answer

d=?
v=0.99c
t=1x10^-7s

nottim · Answer

obviously more complex than that though, eh?

anonymous · Answer

lifetime at rest is give, we have to find lifetime in motion

nottim · Answer

aww bugger. I really wanted this to be that simple.

anonymous · Answer

answer is not coming correct by your expression?

anonymous · Answer

its a time dialation problem related to relativity theory

nottim · Answer

Aww.. How does that make this more complex? Is there like some super tricky thhing going on?

nottim · Answer

heyy?

anonymous · Answer

yeah

anonymous · Answer

we use this eaqution to find t$$t=t_{o} / \sqrt(1-v^2/c^2)$$

anonymous · Answer

then we use d=vt

nottim · Answer

Please be plug and play?

anonymous · Answer

what

nottim · Answer

just plug in variableS?

nottim · Answer

@salini can you help?

nottim · Answer

@Mani Jha or @Espex please help?
MY god I can not do this...

nottim · Answer

yeah..I can't help you. I'm sorry.

anonymous · Answer

life time at rest = 10^(-7) s
life time at speed 0.99c = 10^(-7)/sqrt(1-(0.99*0.99)) = 7.0888 x 10^(-7) s
so, before decaying completely it travels 0.99c x 7.0888 x 10^(-7) m = 210.5377 m