How about this...
\frac {3}{3+\frac {3}{3+\frac {3}{3+\frac {3}{...}}}}

Question

How about this...
\frac {3}{3+\frac {3}{3+\frac {3}{3+\frac {3}{...}}}}

anonymous · Answer

$$\frac {3}{3+\frac {3}{3+\frac {3}{3+\frac {3}{...}}}}$$

anonymous · Answer

x^2 + 3x = 3

lgbasallote · Answer

let x equal that
3/3+x = x
3 = 3x + x^2
x^2 + 3x - 3 =0

-3 +/- sqrt (9 - 4(1)(-3)/2(1)

-3 +/- sqrt (9 + 12) /2

-3 +/- sqrt 21/2

x= 0.7913

lgbasallote · Answer

there seems to be something wrong with my quadratic formula...

x^2 + 3x = 3
x(x+3) = 3
x = 3
x = 0

???

anonymous · Answer

if x=3, isnt the rhs=18? @Igbasallote

anonymous · Answer

and if x=0, rhs=0

lgbasallote · Answer

oh yeah...so my quadratic formula is right...my factor was the one that's wrong =))))))

apoorvk · Answer

|dw:1332670830662:dw|

simplify and enjoy!!!

callisto · Answer

Sorry to ask, how can you guys get to this step: 3/3+x = x ?

apoorvk · Answer

callisto, i hope you can see that first the whole expression's value to be 'x'. then the part in denominator after "3+.." that is just 'x' as well too right?? because the whole equation continues to divided infinite times!!!

callisto · Answer

you let it be x , so it is x...

callisto · Answer

Nah.. it seems i understand a little..