A wedge of mass M is fixed on the horizontal ground. A block of mass m slides down the wedge's smooth surface as shown. What is the normal reaction exerted on the wedge by the ground?

Question

callisto · Answer

I thought it was Mg + mgcosθ but it is was wrong.. Can anyone explain the correct one?

anonymous · Answer

I think it is    mg + Fsin $$\theta$$

callisto · Answer

no, i'm very sure it is not sinθ...

anonymous · Answer

F= frictional force

callisto · Answer

smooth plane.. = no friction ...

amistre64 · Answer

not that im an expert at this, but from looking at the web it looks like Fn = mg cos(t)

callisto · Answer

not correct neither :(

amistre64 · Answer

can you give a reason as to why it aint correct?  i dont even know how to think thru the problem to determine a solution

callisto · Answer

Nah.. the reason is the answer to the question is not like this, and i don't know how the answer comes.. If i knew it , i wouldn't posted it here..

callisto · Answer

The answer to this question is Mg+mg(cosθ)^2... can anyone explain it???

anonymous · Answer

hey callissto can u tell me how u got Mg + Mgcostheta

callisto · Answer

resolve the component mg

anonymous · Answer

show me ur work plz

callisto · Answer

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