Question

A curve is such athat {dy/dx}= {12 over (2x+1)^2} and P(1,5) is a point on the curve.

Um... the last part of the question says, A point is moving along the curve in such a way that the x=coordinate is increasing at a constant rate of 0.3 units per second. Find the rate of increase of the y-coordinate when x=1

Answer 1

4/3

Answer 2

How?

Answer 3

the dy/dx value at x=1

Answer 4

dy = f'(1)x0.3

Answer 5

sorry, 4/3 * 0.3= 0.4

Answer 6

So, how?

Answer 7

dy/dx value is the ratio of rate of change of y wrt rate of change of x.
dy/dx at x=1 is 12/3^2=4/3
rate of change of x= 0.3
so, rate of change of y=4/3 * 0.3= 0.4

Answer 8

thanks!