Question

Express y = 14 - 3x - x^2 in the form y = p(x + q)^2. Hence, find the maximum value of y and the value of x at which the maximum value occurs.

Answer 1

\[\frac{65}{4}-\left(x+\frac{3}{2}\right)^2\]

Answer 2

Maximum at vertex (-3/2, 65/4)
Because the coefficient of x^2 is negative, its a maximum

Answer 3

Thanks again! Any idea how to sketch the graph for y = 14 - 3x - x^2?

Answer 4

THANK YOU, Sam! (:

Answer 5

welcome :)