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How can I resolve this equation by substitution? \[\int\limits{(x^2)/1-x^3}dx\]
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let u = (1-x^3)
let x^3 = y, then 3x^2 = dy
No let u = 1-x^3
du=-3x^2dx
Multiply your integral by: (-1/3)*(-3)
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1/3*int 1/(1-y)*dy
So you'll end up with: (-1/3)Integral((1/u)du)
my method is easier experimentX
yeah ... faster too
both is nice, thank you...
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(-1/3)Ln|u|+C=(-1/3)Ln|1-x^3|+C
Thanks
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