How many moles of calcium hydroxide are needed to produce 73.7 milliliters of water, if the density of water is 0.987 g/mL? Show all steps of your calculation as well as the final answer.

HCl + Ca(OH) 2 → H2O + CaCl2

Question

How many moles of calcium hydroxide are needed to produce 73.7 milliliters of water, if the density of water is 0.987 g/mL? Show all steps of your calculation as well as the final answer.

HCl + Ca(OH) 2 → H2O + CaCl2

anonymous · Answer

Ca(OH)2  + 2HCl  --> CaCl2 + 2H20
Mass of H20: 73.7 ml * .987 = 72.74 g
Moles of H20: 72.74 g/ 18 = 4.04 mol
Thus moles of Ca(OH)2: 4.04/2 = 2.02 mol