A straight line passes through the point (3,0) and meets a variable line y=tx at right angles at point P.Find the coordinates P in terms of t.Find also the value of k, given that P lies on the curve x²+y²=kx
|dw:1333630616897:dw| i think this is the area of concern for the 2 lines
|dw:1333630851328:dw|
from geometry i recall a notion that any triangle that has the diameter of a circle for a hypot; and has legs that hit the outer circle; will always be a right triangle
so the circle that we are concerned with that matches the information is at least: (x-1.5)^2 + y^2 = (1.5)^2 this traces all the points of perpendicular intersection of the 2 lines in question
Well I definitely know that a triangle with a hypotenuse is a right angled triangle,but what do you mean by the legs touching the outer circle ?
P = |dw:1333631264507:dw|
i mean that where the other 2 sides meet up at to form a right angle will meet on the rim of the circle
now if we are looking for a circle that touches a specific spot ON this circle with the criteria that x^2 + y^2 = kx; then that circle will center at the origin
kx = r^2 ; 0 < r < 3 hmm
x^2 + y^2 = 1 --- --- kx kx x + y^2 = 1 - --- k kx 1/k (x + y^2/x) = 1 1/k = 1/x+y^2/x k = x+y^2/x
class beckons me; so good luck
What are the exact coordinates of P then ?
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