Question

how do you solve 2cos(z)cot(z) = 3 ???
If someone can just show the working till it becomes either sin or cos, thats cool :P

Answer 1

cot= cos/sin
cos*cot=cos^2/sin= (1-sin^2)/sin
now, make the quadratic..

Answer 2

Give you something more pretty :)
2cos(z)cot(z) = 3
2cos(z)[cos(z)/sin(z)] = 3
2[cos(z)]^2 = 3sin(z)
2[1-(sinz)^2] = 3sinz
2-2(sinz)^2 - 3sinz =0
2(sinz)^2 + 3sinz -2 =0
Solve the quadratic and work out the answer :)

Answer 3

ohhhhhhh. ha, ha, ha, i feel so stupid right now, its not funny -_-