Question

Solve 2^x + ^3 = 7

Answer 1

Something missing in your question

Answer 2

what is missing? I have to solve 2 to the power (x+3 = 7

Answer 3

oh
\[2^{2x+3}=7\]

Answer 4

yes, exactlly

Answer 5

\[(x+3) = \log_{2}(7) \]

Answer 6

sorry no, the two is only raised to the x+3 power

Answer 7

2^(x+3)=7
Use natural log
ln(2^(x+3))=ln(7)

xln(2)+3ln(2)=ln(7)

xln(2)=-3ln(2)+ln(7)

x=-(3ln(2))/(ln(2))+(ln(7))/(ln(2))

x=(-3ln(2)+ln(7))/(ln(2))_
x=-0.1926

Answer 8

\[x = \log_{2}(7)-3 \]

Answer 9

how do i solve Solve 11.32^(x – 1) = 15.7