Question

What is the integral of e^9x

Answer 1

I[e^(9x)dx]

Replace 9x with u to simplify the integrand.
u=9x

Find an equation relating the value of dx to du.
du=9 dx

Since du=9 dx, then dx=(du)/((9)).
dx=(du)/(9)

Replace the value found for dx so that the integrand is in terms of u.
I[,,e^(u)*(1)/(9),u]

Simplify the integrand.
I[,,(e^(u))/(9),u]

The integral of (e^(u))/(9) is (e^(u))/(9).
(e^(u))/(9)+C

Replace u=9x in the solved integral to find the solution in terms of x.
(e^(9x))/(9)+C


NOTE: I=Integral

Answer 2

after comma. it is du (,u)

Answer 3

I'm kind of confused at the part where you put the integrand in terms of x. Why is there a second u at the end (after the comma)?

Answer 4

where? line no. please.