does anyone know how to determine interval using < and > signs
you mean solve inequalities?
or interval notation?
i got a question to find the missing numbers and plot the graph and determine the intervals for which f(x)\[\ge\]0
ok, what are the numbers?
and what is f(x)
first you have to find when f(x)=0, this divides the domain up into intervals. you then test a sample from each interval to see if its positive, negative, or zero
also find when f(x) is undefined
yes i did that but it is suppose to look like this: -3x^2+4x+4<0 x<-0.666 or x>2
x -3,-2,-1.5,-1,0,1,2 f(x) -7,0,2,3,2,-3,-12
3x^2-4x-4>0 3x^2-4x-4=0 3x^2-6x+2x-4=0 3x(x-2)+2(x-2)=0 (x-2)(3x+2)=0 x=2, -2/3 this divides the domain up into three intervals (-infinity, -2/3), (-2/3, 2), (2, infinity)
After plotting the graph for that it asks 3 questions: i. The coordinates of the maximum point ii. The interval for whichf(x) ≥ 0 iii. The interval for which f(x) ≤ 0
so here you test a value from each interval. for the first interval we'll test x=-1 (x-2)(3x+2)>0 (negative)(negative)>0, true, this interval is part of the solution 2nd interval, we'll use 0 (negative)(positive)>0 false, this is not part of solution 3rd interval, we'll use x=3 (positive)(positive)>0, true, this is part of solution solution set: (-infinity, -2/3)U(2, infinity)
Im doing college algebra
so your question was which one?
did you plot the graph?
the last 2, yes I did the graph already
what was the shape of graph? parabola?
it is mountain shaped
let me plot it, 1 second
f(x)=2-3x-2x^2
yes i just did a regression and got -2x^2-3x+2, it is a parabola
ok
website crashed on me
the maximum can be solved by finding the y-coordinate of the vertex, it's a maximum because the parabola opens down
for that i got -1,3
you got -1, 3 for what?
the maximum point
not quite, from the regression we have f(x)=-2x^2-3x+2
the vertex is at (3/[2(-2)], f(3/[2(-2)]) or (-3/4, 25/8)
so the max value is 25/8
ok I think you are more advance for what the instructor wants he said to look at the graph and just write down the coordinates of the max point
ah ok, but does he want you to solve the inequalities or just look at the graph?
yes I solved it but he want it in a format that I'm not so clear on
interval notation?
or set-builder notation?
I solved it ad got: 0.5 and -2
ok, so now you have the intervals you need to solve the inequality
in and example he has x^2-3x+2>0 answer: x<1 or x>2
this splits the domain into 3 intervals
ok so you have the zeros of f(x) in your question, 1/2 and -2
so the factored form of f(x) is (2x-1)(x+2)
but I solved the inequality 2-3x-2x^2|dw:1332811990724:dw| and got 0.5 and -2
you didn't solve the inequality, you solved the equation 2-3x-2x^2=0
it was not equal to 0 it was greater than or equal to 0
yeah, that's the next step, solving the inequality, which is easy when you found the zeros
|dw:1332812190676:dw|
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