A sample of chromium weighing 465 g was initially at a temperature of 26.45 degrees Celsius. It required 1027 joules of heat energy to increase the temperature to 31.35 degrees Celsius.

1. What is the specific heat capacity of the Chromium
2. What is the molar heat capacity of the Chromium
3. What is the heat capacity of the Chromium

Question

A sample of chromium weighing 465 g was initially at a temperature of 26.45 degrees Celsius. It required 1027 joules of heat energy to increase the temperature to 31.35 degrees Celsius.

1. What is the specific heat capacity of the Chromium
2. What is the molar heat capacity of the Chromium
3. What is the heat capacity of the Chromium

anonymous · Answer

use our handy dandy q=(m)(Csp)(deltaT) where m is mass Csp is obvious and deltaT is the change in temp(final - initial) and q is energy. We get 1027J/(465g)(31.35-26.45) = .451 J/gC. Molar heat capacity would be the same except convert the grams to mols by dividing grams by chromium's molar mass. Heat capacity is the same equation with out mass so just solve q/deltaT = C