Question

HIII/HELP who can help with both or one of these precalc questions my last two!!!!**

Answer 1

First one, if 5cos(x) =5/2, then cos(x)=1/2. Can't remember my trigonometric circle by heart, but I bet you have that lying around somewhere on your desk

Answer 2

So cos x = 1/2 which indicates x= pi/3, 5pi/3, 7pi/3, or 11pi/3

Answer 3

Remember that cos x = 1/2 comes from a 30/60/90 triangle.

Answer 4

\[\sqrt{\csc^2(\theta)-1}=\sqrt{\frac{1}{\sin^2(\theta)}-1}=\sqrt{\frac{1-\sin^2(\theta)}{\sin^2(\theta)}}=\sqrt{\cot^2(\theta)}=\cot(\theta)\]

Answer 5

how does x= pi/3, 5pi/3, 7pi/3, the same thing as=== 11pi/3?

Answer 6

and so what is the answer for the second one out of all of that? animalain!?

Answer 7

there are 2 values between 0 and 2pi where cos(x) = 1/2, pi/3 and 5pi/3. To find the values for 2pi to 4pi, you just add 2pi to those first values

Answer 8

pi/3 is in quadrant one; 5pi/3 is in quadrant four. 7pi/3 and 11pi/3 are on the second lap, since we are going for theta in [0,4pi]

Answer 9

soo the final answer!? im still confused im gonna have to go to tutoring tomorrow but so x=?

Answer 10

The problem goes from left to right. The answer is on the right.

Answer 11

what does it mean when it says (Enter the argument of the trigonometric function in parentheses.) is that the theta sign

Answer 12

Steps for my solution of problem two above:
1. Problem statement.
2. Substitute definition of csc.
3. Rephrase argument of radical as single rational expression.
4. 1- sin^2 = cos^2 then argument is cot^2
5. Square root of cot^2 is cot.

Answer 13

The argument is the value or expression you put into the function, radical, absolute value, etc.

Answer 14

cot(theta) wasnt right :(

Answer 15

= - cot(theta)

Answer 16

Good catch. The function is negative in the second quadrant, and the answer is positive, so we need the negative sign to make it all play nice.