In △PQR, what is the length of QR posting pic now
\[21\sqrt{2}\] \[42\sqrt{2}\] \[42\sqrt{3}\] 21
What are the directions of the problem. Are you allowed to use trig functions?
Because trig is the easiest way.
\[\sin 45=\frac{QR}{42}\]
im sure i can if u get one of them answers
plus or minus 21
use Pythagoras theorem
It can't be minus if we are talking about a lenght @King
There are rules for a 45, 45, 90 triangle. Just like with a 30,60,90 http://zonalandeducation.com/mmts/miscellaneousMath/tri454590306090/tri454590306090.htm So, 42/2*sqrt(2)
oh yeah sry 21
use Pythagoras theorem
That is one of the special right triangles. The 45-45-90. In such a triangle you multiply a leg by sqrt2 to find the hypotenuse. Correspondingly, you divide they hypotenuse by sqrt2 to find the leg. You are trying to find the leg.
\[\frac{42}{\sqrt{2}}=\frac{42\sqrt{2}}{2}=21\sqrt{2}\]
ohh okay but someone else said it was the 42/2 so which one idk i dont have a teacher really im homeschooled
\[21\sqrt{2}\]Is the right answer mak_12
Maybe macnaljj made a typo.
42/2 is 21. I was pointing out that h/2*sqrt(2) is the rule for the other sides. Could have done better.
can someone help me with the question i just posted n then tell me how and its okay no promblem there @mcnalljj
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