Find the Derivative of G= ((5x^4)+(2x)-(1/4))/((x^3)-(cos(5)))
20x^3 + 2 + 3x^2/4*1/((x^3)-(cos(5))^2
Wow, that was really fast, I was going to get back on tomorrow. I appreciate it.
@Headdesk Yes, we're really fast
just a matter of practice ... derivative is not so difficult after all
where is the 3x^2 coming from?
Clearer form: \[\frac{-16 x^3 (5 \cos (5{}^{\circ})+1)-8 \cos (5{}^{\circ})+20 x^6+3 x^2}{4 \left(x^3-\cos (5{}^{\circ})\right)^2}\]
I refuse to just take answers without learning something
\[\text{Use the quotient rule, }\frac{d}{dx}\left(\frac{u}{v}\right)=\frac{v \frac{du}{dx}-u \frac{dv}{dx}}{v^2}\text{, where }u=5 x^4+2 x-\frac{1}{4}\text{ and }v=x^3-\cos (5{}^{\circ}):\]
The page was not large enough \[v=x^3-\cos (5{}^{\circ})\]
okay, I am going to write this down. Thanks again.
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