Question

logbase3(1/9)=x find x please explain

Answer 1

can you use equation it is hard to understand

Answer 2

but the answer can be -2

Answer 3

\[\log_{3}(1/9)=x \]

Answer 4

No answer is -2

Answer 5

x=logbase3(1/9)
= logbase3(1) - logbase3(9)
= 0 - logbase3(3^2)
= - 2logbase3(3)
= -2

Answer 6

\[3^1=3\]\[3^0=1\]\[3^{-1}=\frac13\]\[3^{-2}=\frac19\]in general\[a^{-n}=\frac1{a^n}\]

Answer 7

then \[\log_{3} (3^{-2}) \]
\[-2\log_{3} (3)\]
-2

Answer 8

\[\log_3(\frac19)\]is like asking
"what power do you raise 3 to to get 1/9?"
the answer is -2