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OpenStudy (anonymous):
How would you find the horizontal asymptote of
f(x)=(x^2-16)/(x+3) Thanks!!
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OpenStudy (anonymous):
differentiate and put \[f \prime(x)=0\] find value of x and then f(x)
y=f(x) will be the answer
OpenStudy (anonymous):
Okay, so then I honestly still have no idea what to actually write as my answer
OpenStudy (anonymous):
y=2or -8 two of them would be there
OpenStudy (anonymous):
okay, thanks!!
OpenStudy (anonymous):
medal please
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OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
I was getting there :P
OpenStudy (anonymous):
there is a small mistake that i made the answer is y= -48/5 or -12/5
OpenStudy (anonymous):
@annas My question is Solve 3^(x-4) = 7^(x+9) Thanks!
OpenStudy (anonymous):
ok.... np
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OpenStudy (anonymous):
\[3^{x-4} = 7^{x+9}\]
OpenStudy (anonymous):
(x-4)log3=(x+9)log7
(x-4)(0.4771)=(x+9)(0.8450)
0.4771x-1.908=0.8450x+7.605
-1.908-7.605=0.3679x
OpenStudy (anonymous):
The answers are
A x ≈ –2.59
B x ≈ –25.86
C x ≈ –0.39
D x ≈ –0.04
OpenStudy (anonymous):
-9.513=0.3679x
x=-25.857
OpenStudy (anonymous):
its B
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OpenStudy (anonymous):
Thank you so much!!!!!
How else can I give you a medal?
OpenStudy (anonymous):
no need of medals i dont work for medals i love helping boy :) and welcome
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
no need of that either boy ...
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