Question

1

Answer 1

use ruffini

Answer 2

there is a zero between x = 0 and x = 1

this is because f(0) = 3 and f(1) = -4

use Newtons method for approximating the root

\[x _{1} = x_{0} - f(x _{0})/f'(x _{0})\]

let \[x _{0} = 0.5\]

there also appears to be a root between x = -3 and x = -2

f(-3) = -24 f(-2) = 37

choose \[x_{0} = -2.5\]

and a root exists between x = 1 and x = 2

f(1) = -4 and f(2) = 1

this is the best method I can think of