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Mathematics 7 Online
OpenStudy (shayaan_mustafa):

Find the equation for the family of lines tangent to the circle with center at the origin and radius 3.

OpenStudy (shayaan_mustafa):

I know, use the equation y=mx+c. But how?

hero (hero):

First draw the circle

OpenStudy (shayaan_mustafa):

|dw:1332964463602:dw|

hero (hero):

Yes, but, well I also believe we should apply equation of a circle as well to this

OpenStudy (shayaan_mustafa):

tangent is perpendicular to the radius of the circle. and slope of perpendicular line are m1=-1/m2. right??

hero (hero):

yes

OpenStudy (shayaan_mustafa):

let us simplify the question first. we just find the equation of tangent line and then find the family. OK

hero (hero):

Let me get back to you regarding this question. I think they want more than just the equation of a tangent line at one point on the circle. I think they want an equation of a tangent for any point on the circle

OpenStudy (shayaan_mustafa):

yes yes. exactly. family of line implies this idea as you said. but if we find equation for one tangent the we can find equation for any tangent. family too.

OpenStudy (shayaan_mustafa):

did you get my idea?

hero (hero):

if you found an equation for one tangent, you would not be able to find it for another tangent. That would only work if (3,0), (-3,0)(0,3)(0,-3) were the points

hero (hero):

You would already have to know the points in advance for any other point on the circle in order to find the equations of tangent lines

OpenStudy (shayaan_mustafa):

look Hero. y=-x+c is the family of line which has same slope. do you know this idea? If so then why not for above question?

hero (hero):

What concepts are you studying in class regarding this? Are you working from a textbook? If so, tell me the name of the section you're working on.

OpenStudy (shayaan_mustafa):

Calculus by howard anton. 7th edition

hero (hero):

Oh, I see. This is calculus. I thought you were doing high school geometry

OpenStudy (shayaan_mustafa):

it is university level.

OpenStudy (turingtest):

our circle is\[x^2+y^2=9\]the formula for a tangent line at a point 'a' is\[y-y(a)=y'(a)(x-a)\]I think we should differentiate implicitely to get y'

OpenStudy (shayaan_mustafa):

no. differentiation is not include up to this section. so we can't differentiate it.

OpenStudy (turingtest):

eh? um.... then how is it calculus?

OpenStudy (shayaan_mustafa):

look look.. it is 1st chapter named functions and differentiation is starting from chap#3

OpenStudy (shayaan_mustafa):

no one can help me on this problem :(

OpenStudy (turingtest):

ok um... let's see if we can be creative based on what we know from functions and trig the following are tangent lines to the circle\[x=\pm3\]\[y=\pm3\]that covers four sides|dw:1332966190330:dw|now we need to develop some formulas for the areas in between the top, bottom, left, and right

OpenStudy (turingtest):

hm...|dw:1332966361060:dw|here is a tangent line at some mystery point, I wonder if we can divine a formula for the slope of it

OpenStudy (shayaan_mustafa):

heheheheh... divine..

OpenStudy (turingtest):

|dw:1332966453442:dw|maybe we can use some trig here...

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