Your starship, the Aimless Wanderer, lands on the mysterious planet Mongo. As chief scientist-engineer, you make the following measurements: a 2.50-kg stone thrown upward from the ground at 15.0 m/s returns to the ground in 6.00 s; the circumference of Mongo at the equator is 4.00×105 km; there is no appreciable atmosphere, and the planet's mass is 3.04*10^26 kg. If the Aimless Wanderer goes into a circular orbit 3.00×104 km above the surface of Mongo, how many hours will it take the ship to complete one orbit?

Question

mani_jha · Answer

$$Time=Distance(2pir)/Speed(\sqrt{GM/r)}$$
r=Radius of Planet+3X10^4

mani_jha · Answer

Clear?

anonymous · Answer

first u got to find the velocity with which the man orbits the planet
centripetal force is provided by the graviational force of attraction GmM/r^2
so 
mv^2/r=GmM/r^2
find expression for velocity 
next 
speed=distance/time
so time=distance/speed
i know speed wat abt the distance?
man goes in a circular orbit hence the orbits radius is R
perimeter=2*pi*R
|dw:1333021692767:dw|
note the diff btw R and r(radius of planet)