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Mathematics 21 Online
OpenStudy (anonymous):

The area of the front face of the analog clock shown below is 50.24 square inches. The length of the minute hand is 0.25 inches less than the radius of the front face. What is the length of the arc the minute hand makes when it moves from the number 3 to the number 7 on the clock?

OpenStudy (anonymous):

OpenStudy (anonymous):

can you find the circumference of the circle the minute hand makes as it goes around?

OpenStudy (anonymous):

then multiply that by 1/60 for every minute it sweeps in your arc

OpenStudy (anonymous):

I got the circumference of 25.12, would that be correct?

OpenStudy (anonymous):

you can also use s = r * theta, where s is the length of the arc, r is your radius, theta is the angle created between 3 and 7 on the clock. theta MUST be in radians.

OpenStudy (anonymous):

I'm still not entirely sure how to solve this problem or where to start

OpenStudy (anonymous):

well, you know the surface are of the clock... so what is the radius? can you do that?

OpenStudy (anonymous):

would the radius be 4?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

now subtract the gap for the minute hand to get the radius of the smaller circle

OpenStudy (anonymous):

then get that circumference

OpenStudy (anonymous):

i got 11.775 for the circumference

OpenStudy (anonymous):

what is the formula for circumference and what is the radius you used?

OpenStudy (anonymous):

not saying you are wrong, but that is half of what I thought it was

OpenStudy (anonymous):

I used the radius 3.75 and but i forgot to multiply by 2, oops. I got the answer of 23.55 just now. I used the forumla 2 * 3.14 * 3.75

OpenStudy (anonymous):

ok, thats what I thought it was... maybe we are both right (crossing fingers)

OpenStudy (anonymous):

so every minute sweeps out 1/60 of that 23.55 inches...

OpenStudy (anonymous):

and you want to know how far it swept in 4 minutes...

OpenStudy (anonymous):

so would i multiply 1/4?

OpenStudy (anonymous):

no that would be 15 minutes (dont get confused) how many inches does it go in one minute? remember it goes 23.55 inches in 60 minutes

OpenStudy (anonymous):

2.54? I got that by dividing 23.55 into 60

OpenStudy (anonymous):

ok, step back and think about that... does the minute hand move 2.54 inches every minute? when it moves 23.55 inches in an hour?

OpenStudy (anonymous):

I think you did it backwards... should be a very small answer

OpenStudy (anonymous):

so what would i do to figure out how far it moves

OpenStudy (anonymous):

23.55/60 should tell you how many inches that sucker moves every minute

OpenStudy (anonymous):

so how far does it go in 4 minutes?

OpenStudy (anonymous):

0.3925

OpenStudy (anonymous):

and in 4 minutes?

OpenStudy (anonymous):

1.57 in four minutes

OpenStudy (anonymous):

1.57 what? and yes, I think that is the answer to this puzzle

OpenStudy (anonymous):

well the answer options i was given for this question were 1.31 inches 7.85 inches 8.37 inches 23.55 inches so i'm not sure if it could be that many inches

OpenStudy (anonymous):

so where did we/I mess up? hmmm

OpenStudy (anonymous):

circumference is 2 pi r ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok I got it it is not 4 minutes... it is the minutes between the 3 and the 7 on the clock how far did that sucker go in 20 minutes?

OpenStudy (anonymous):

7.85!

OpenStudy (anonymous):

so we didnt mess up after all, well, not much... have a great day

OpenStudy (anonymous):

thanks :)

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