Question

int. x2^xdx

Answer 1

\[\int\limits_{?}^{?}x2^{x}dx\]

Answer 2

Use integration by parts.That should do it.

Answer 3

should i set u=2^x and dv=xdx?

Answer 4

∫x/(2-x) dx

First, rewrite the numerator in terms of x-2:

∫(x-2)/(2-x) + 2/(2-x) dx

Simplify the first fraction:

∫-1 + 2/(2-x) dx

Now integrate (remembering to use the inverse chain rule on the second term):

-x - 2 ln |2-x| + C

Answer 5

^what? does it relates to my question?

Answer 6

just a conceptual clearance

Answer 7

i sent u a message

Answer 8

regarding this

Answer 9

no set .... u = x dv= 2^x
du = dx v = 2^x/ln(2)