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Mathematics 24 Online
OpenStudy (anonymous):

why e^lnf(x) = f(x), where can I FIND the proof of it?

OpenStudy (anonymous):

e^lnf(x)=e^log(e)(f(x))=f(x)

OpenStudy (anonymous):

that's it, is it a proof? it just flew over my head :|

OpenStudy (turingtest):

by definition of the lgarithm\[\log_ax=y\iff x=a^y= a^{\log_a x}\]

OpenStudy (anonymous):

ok, that right

OpenStudy (turingtest):

no ngoc... just restated the problem and proved nothing no offense...

OpenStudy (savvy):

let \[y = e^{lnf(x)}\] taking log on both sides... \[\ln y = \ln e^{lnf(x)}\] since\[lnx^m = mlnx\] so \[lny = lnf(x)lne\] also ln(e) = 1 so lny = lnf(x) so y = f(x) but \[y = e^{lnf(x)}\] so \[f(x) = e^{lnf(x)}\]

OpenStudy (anonymous):

ok, the same

OpenStudy (anonymous):

it is definition

OpenStudy (anonymous):

thanx @ savy

OpenStudy (anonymous):

@Savvy very rigour proof

OpenStudy (turingtest):

did you follow mine wounded tiger? it may not be as elaborate, but I think it is solid

OpenStudy (savvy):

lol...your welcome dude...

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