Hey, just trying to understand the intuition of functions a bit better. f(x) = -5 if x = -2, f(x) = -3x^2 + 4 otherwise. The 4 is the y-intercept, and the -3x squared is the slope, right? Is the -3x squared because the parabola is symmetrical?
You can get the slope by differentiating\[-3x^2 + 4\] to get the slope function as: \[-6x\]
Can you please rephrase your question?
What is the range? but i'd like to know if the 4 is the y-intercept and the -3x^2 is the slope, and if possible can you show me on a graph?
-3x^2 is NOT the slope.
4 is the y-intercept because at x = 0, f(x) = -3(0)^2 + 4 = 4 The slope is -6x, have you use differentiation before?
you can find the slope of the curve by dy/dx. (if you have studied calc)
no not yet, AsianDuck
Ah, i'm just starting calc, that's prob why i don't really get the intuition yet
y = mx + b here you can apply the logic that "m" is the slope. but u have a quadratic equation here. where the slope will change on every step.
can you please explain differentiation?
but if f(x) = -3x^2 + 4 (wouldn't that count as y = mx + b) with the -3x being the slope??
you have a QUADRATIC EQUATION sir. with "x^2" whereas in linear equation there is "NO x^2" there's only "x"
ah okay :D thank you
any more confusions? i can feel the happiness.
Join our real-time social learning platform and learn together with your friends!