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Find vector equation for the line with the following cartesian equation. b) x+3y=7
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1; 3
r = (1,2) + t(0,1) is the answer..... but why?
r = ( 1,2) + t(1 ; 3) ?
i cant tell
sorry, it's (1,2) + t(3, -1)
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yes, let point in line is ( 1; 2) , after let vertices caster : (1; 3 ) => ( 3; -1) or ( -3; 1)
So, how do you do this in steps? W/o knowing the answer?
x=1 , 1 + 3y = 7 => y =2 . have M(1; 2) coefficient x : 1 ; coefficient y : 3 = > vertices perpendicular ( 1; 3) => vertices parallel ( -3, 1) ==> r = ( 1;2) + t(-3;1) ok?????
or ==> r = (1, 2) + t(3; -1)
hmm. ok
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